(5x^2/3)+6=20

Solution for (5x^2/3)+6=20 equation:

(5x^2/3)+6=20

We move all terms to the left:

(5x^2/3)+6-(20)=0

We add all the numbers together, and all the variables

(5x^2/3)-14=0

We get rid of parentheses

5x^2/3-14=0

We multiply all the terms by the denominator


5x^2-14*3=0

We add all the numbers together, and all the variables

5x^2-42=0

a = 5; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·5·(-42)
Δ = 840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{840}=\sqrt{4*210}=\sqrt{4}*\sqrt{210}=2\sqrt{210}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{210}}{2*5}=\frac{0-2\sqrt{210}}{10}
=-\frac{2\sqrt{210}}{10}
=-\frac{\sqrt{210}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{210}}{2*5}=\frac{0+2\sqrt{210}}{10}
=\frac{2\sqrt{210}}{10}
=\frac{\sqrt{210}}{5}
$